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1 label code, 2 determine time complexity of code segments ,

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1. Find one example of each label in the following source code and write the line number of the example next to the label.

a. Instance variable

b. Class variable :

c. Instance method

d. Class method

e. Constant variable

f. Constructor

g. Import statement :

1: package edu.gmu.cs.geom;
3: import edu.gmu.cs.geom.Translatable;
5: public class Point2d implements Translatable {
7: public static int ORIGIN_X = 0;
8: public static int ORIGIN_Y = 0;
10: private int x;
11: private int y;
13: public Point2d() {
14: this.x = Point2d.ORIGIN_X;
15: this.y = Point2d.ORIGIN_Y;
16: }
18: public Point2d(int x, int y) {
19: this.x = x;
20: this.y = y;
21: }
23: public int getX() {
24: return this.x;
25: }
27: public int getY() {
28: return this.y;
29: }
31: public void translate(int xDelta, int yDelta) {
32: this.x += xDelta;
33: this.y += yDelta;
34: }
36: public static Point2d add(Point2d left, Point2d right) {
37: int x = left.getX() + right.getX();
38: int y = left.getY() + right.getY();
40: return new Point2d(x, y);
41: }
43: }

2. Order the following code segments by time complexity in ascending order. For bonus points, show the runtime of each code segment in Big O notation.


for (int y = 0; y < n; y++) {
for (int x = 0; x < n; x++) {
m[y, x] = 0;


public boolean isOdd(int x) {
return (x % 2) == 0;


int x = 0;
int y = 0;

while (x < MAX) {
if (isOdd(x)) {
} else {


int sum = 0;
for (int i = 0; i < items.size(); i = (i * 2) + 1) {
sum += items.get(i);

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Solution Preview

Question #1
a. Instance variable
10: private int x;
b. Class variable :
7: public static int ORIGIN_X = 0;
c. Instance method
23: ...

Solution Summary

The expert determines the time complexity of code segments for a label code are examined.

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