Explore BrainMass

Explore BrainMass

    Local Area Networks

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Suppose you are the network manager for Central University, a medium-size university with 13,000 students. The university has 10 separate colleges (e.g., business, arts, journalism), 3 of which are relatively large (300 faculty and staff members, 2,000 students, and 3 buildings) and 7 of which are relatively small (200 faculty and staff, 1000 students, and 1 building). In addition, there are another 2,000 staff members who work in various administration departments (e.g library, maintenance, finance) spread over another 10 buildings. There are 4 residence halls that house a total of 2,000 students. Suppose the university has the 128.100.xxx.xxx address range on the Internet. BRIEFLY describe how would you assign the IP addresses the various subnets? How would you control the process by which IP addresses are assigned to individual computers? You will have to make some assumptions to answer both questions, so be sure to state your assumptions.

    © BrainMass Inc. brainmass.com March 4, 2021, 9:26 pm ad1c9bdddf

    Solution Preview


    Please find the solution in the attached file.

    Please do let me know, if you have any query.


    The network address of university is This is a class B network.
    Number of valid host in this network is =256*256 -2 = 65534
    Since university has 10 collge there should be subnetting.
    While using subnetting we need to give a network address and a subnet mask.
    For example say network address Now, we are using subnet mask i.e 11111111.11111111. 11111111.00000000 for subnettting
    Subnet mask has 2 parts -:
    i) Net id-which represents network id and remains constant per network.
    Here in class B subnet mask first 16 bit represent Net id.
    ii) Host id- Represents Node id and can change from 0 to 255 per network. Here in class B next 16 bits represents host id.

    Now in a subnet, Number of valid host = ((2^y)-2), where y = number of zero bits in host id.
    In the above example number of valid host = (2^8)-2=254. Since 2 addresses are used for network address and broad cast address, therefore 265-2=254 hosts.
    Number of valid small network = 2^x, where x represents number of 1's in host id.
    In the above example, number of valid small network in (subnet) in network is (2^8) = 256. This 256 network each network will have 256 address.

    Now let come to the problem:
    • We are using variable length subnet mask (VLSM) since different subnet has different number of nodes.
    Since three colleges are very large we will give them a subnet mask of
    i.e. 11111111.11111111.11110000.00000000
    Number of zero's in host id = 12
    So number of valid host in each of these subnet = (2^12-2) =4094
    • First college will have a network address of and subnet mask
    It will have a range of address from ...

    Solution Summary

    The local area networks are examined.