Purchase Solution

Data Communications

Not what you're looking for?

Ask Custom Question

Please explain how you arrive at the answers so I can get a better understanding of them.

(1) A 4480-octet datagram is to be transmitted and needs to be fragmented because it will pass through an Ethernet with a maximum payload of 1500 octets.

Show the total length, More Flag, and fragment offset values in each of the resulting fragments.

(2) Describe some circumstances where it might be desirable to use source routing rather than let routers make the routing decision.

Purchase this Solution

Solution Summary

This posting contains answers to the given questions.

Solution Preview

1. In a 4480-octet IP datagram, there is a header that consists of 20 octets. Therefore, there are 4460 octets for the data field. An Ethernet frame has 1500 octets, consisting of 20 octet headers and 1480 data octets.

To fit the 4460 data octets carrying 1480 data octets per Ethernet frame, we have:
# of datagrams= 4460 / 1480 = 3, remainder 20 octets.

So we have 3 datagrams ...

Purchase this Solution


Free BrainMass Quizzes
C# variables and classes

This quiz contains questions about C# classes and variables.

Excel Introductory Quiz

This quiz tests your knowledge of basics of MS-Excel.

Word 2010: Tables

Have you never worked with Tables in Word 2010? Maybe it has been a while since you have used a Table in Word and you need to brush up on your skills. Several keywords and popular options are discussed as you go through this quiz.

Basic Networking Questions

This quiz consists of some basic networking questions.

Java loops

This quiz checks your knowledge of for and while loops in Java. For and while loops are essential building blocks for all Java programs. Having a solid understanding of these constructs is critical for success in programming Java.