Share
Explore BrainMass

Solutions, Precipitations, and Balancing Equations

1 - Presuming that these molecules are soluble, tell what ions are "produced" upon dissolving.

Rb2SO4 NaC 2H3O 2 AlCl3

2 - Calculate the molarity of
13.2 g of NaOH dissolved in 250 ml of water
27 g of C6H 12O6 in 400 ml of water

3 - How many grams of BaCl2 would you need to make 200 ml of a 0.75 M solution ?

4 - If acetic acid is being stored as a 6M solution, how many ml would you need to make up 200 ml of a 0.17 M solution ?

5 - What mass of aluminum hydroxide can be made from 50 ml of 0.25M Al(NO3)3 and 100 ml of 0.1 M KOH?

6 - What if any precipitate will form from the mixing of these pairs of solutions ?
MgCl2 & AgNO3 KCl & (NH4)2SO4

7 - Na2CO3 + Pb(NO3)2
a. What ions do these split into in water
b. Write a balanced molecular equation
c. Write a complete ionic equation
d. Write a net ionic equation

8 - Write a molecular equation and a net ionic for the combining of (NH4)2S and CoCl2

9 - Complete and balance the following acid-base reactions

HCl + Ca(OH)2 ----->

H2SO4 + Sr(OH)2 ----->

10 - Write a balanced equation for the reaction of sodium bicarbonate and hydrochloric acid

11 - Assign oxidation states for each element
H2
MnO2
MnO4-
HCO3-
SCl5

12 - Fe2O3 + 3 CO -----> 2 Fe + 3 CO2

Identify the atoms that are oxidized and reduced and ID the oxidizing agents and the reducing agents.

13 - What volume of 0.150 HNO3 solution is need to neutralize 25.0 ml of 0.103 M NaOH?

Solution Preview

1- Presuming that these molecules are soluble, tell what ions are "produced" upon dissolving.

Rb2SO4 NaC 2H3O 2 AlCl3

From Rb2SO4, we could obtain Rb+, SO42- ions
From NaC3H3O2, we could obtain Na+ and C2H3O2- ions.
From AlCl3, we could obtain Al3+ and Cl- ions.
2- Calculate the molarity of

13.2 g of NaOH dissolved in 250 ml of water

Molar amount of NaOH: 13.2/40=0.33 mol
Molarity of NaOH: 0.33/0.25=1.32 M

27 g of C6H 12O6 in 400 ml of water

Molar amount of C6H12O6: 27/(30*6)=0.15 mol
Molarity of C6H12O6: 0.15/0.4=0.375 M

3- How many grams of BaCl2 would you need to make 200 ml of a 0.75 M solution ?

Molar amount: 0.2*0.75=0.15 mol
Mass of BaCl2: 208.23*0.15=31.2345 g.

4- If acetic acid is being stored as a 6M ...

Solution Summary

The molecules which are soluble are determined. Solutions, precipitations and balancing equations are provided.

$2.19