How many grams of KNO3 can be made from 591.9 g KCl and 830.0 ml of 12.0 M HNO3 by the reaction:
KCl (s) + HNO3 (aq) ----> KNO3 (s) + Cl2 (g) + NOCl (g) +H2O (I)
Also, how much of the excess reactant (grams if KCl or ml if HNO3) will be unused?
First you need to balance the reaction:
3KCl (s) + 4HNO3 (aq) = 3KNO3 (s) + Cl2 (g) + NOCl (g) +2H2O (I)
So we see that 3 moles of KCl reacts with 4 moles of HNO3. Lets calculate the ...
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