Moles in Bromine

Related BrainMass Solutions

• Ideal Gas Law: Bromine and Flourinne

  n = 0.009320 mol molecular weight = mass / moles = 1.632 g/ 0.009320 mol = 175.1 g/mol Compare that molecular weight to those of bromine triflouride, bromine pentaflouride or dibromine hexaflouride. BrFsub3 137 g/mol NO!

• The Limiting Reagent and Percent Yield

  Using the density of bromine liquid (I found it to equal 8.25 g/mL from an online periodic table) we can see that we have 1.65 grams of bromine, which equals 0.01 moles of bromine. 3.

• Which chemical compound has the greatest mass of bromine?

  The mass of bromine in each compound is calculated by determining the number of moles of each compound, the number of moles of bromine in each compound and then the mass of bromine of that number of moles.

• Basic Chemistry Problems

  Therefore: 96.7 grams of aluminum are 96.7/27 = 3.58 moles of aluminum. 4. Bromine has an atomic molar mass of 80 grams per mole.

• Percent Mass and Stoichiometry

  You take 9.000 g of this mineral and treat it with excess bromine (bromine reacts with iron metal to produce iron(III) bromide, which is soluble in water).

• Decolorize bromine in carbon tetrachloride

  One important test for alkenes and alkynes is the bromine test in carbon tetrachloride. Most organic compounds with at lease one double or triple bond will give a positive test (i.e. decolorize the bromine).

• Organic chemistry problems: Naming, Isomerism, pH

  Kb for ammonia is 1.8*10-5 Molecular weight of Ammonium Chloride = 14+4+35.5 = 53.5 g/mol Therefore, moles of Ammonium Chloride present in 17.8 grams = 17.8/53.5 = 0.3327 NH4Cl(s)  NH4+(aq) + Cl-(aq) NH4+ is an acidic ion and Cl- is a neutral ion

• Acid - Common Component; Calculate Moles; Melting Point; VSEPR Theory; Ionic etc.

  Question 2 Calculate the number of moles of aluminum in 96.7g of Al. a) 0.28 b) 3.6 c) 7.4 d) 4.2 Question 3 The melting point of bromine is -7°C. What is this in °F?

• Stoichiometry Problems, Limiting Reagent, Acid/Base, Balancing Chemical Equations

  We've got 68 grams of mercury and 12.4 grams of bromine. Convert them to moles, see which one is less. That's the limiting one. Then, use that number of moles to figure out how many moles of product you form.