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Molarity Dilution Concentration
Remember: Concentration = Number of mole/Volume
How many mole of I2 in original solution?
Mole = 0.005*0.5*E-3 = 2.5*E-6 (mol)
After mixing, the new volume is 4 ml.
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Mole ratio, molarity, concentration, volume
60466 Mole ratio, molarity, concentration, volume Mole ratio, molarity, concentration, volume
11.84
How many milliliters of 0.120 M Al2(SO4)3 would react completely with 48.0 ml of 0.150 M BaCl2?
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Solutions, Acids, Bases Molarity of a Solution
Calculate the molarity of a solution if 126 mL of 6.25 M NaOH was diluted to a total volume of 250mL.
Number of moles of NaOH = Volume of Solution * Molarity = 0.126*6.25 = 0.7875
Molarity after dilution = 0.7875/0.25 = 3.15M
4.
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Solubility, Molar conc., Molarity, Application of ideal gas equation.
(mol/l) x Volume(l)
0.9161 mole = 1.8427 mol/l x Volume(l)
Volume = 0.9161 mole
1.8427 mol/l
= 0.4972l
= 497.2ml
% of the volume = 39.9ml x 100
497.2ml
= 8.02% The solubility of molar concentration
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Titrating hydrochloric and acetic acids with NaOH
Titration 1:
Volume of NaOH 1.0M used = 15 (mL) - just before solution turns pink
Number of mole of NaOH used =Molarity*volume=1*0.015= 0.015 (mol)
The reaction between HCl and NaOH is:
HCl + NaOH = NaCl + H2O
Hence number of mole of HCl = Number
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Concentration of thiosulfate, molarity
66769 Concentration of thiosulfate, molarity Calculate concentration of thiosulfate ion, S2O3^2-, when 1.00 mL of .00500 M Na2S2o3 are added to experiment. 1 mole of Na2S2O3 in solution will dissociate to give 2moles of Na+ ions and one mole of S2O32
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Molarity, Molar Mass, Oxidizing Agents, Mole Fraction and More
(B)We know that Molarity = Number of moles/Volume in L
= Weight of compound/(Molecular Weight * Volume)
Therefore, weight of compound required = Molarity*Molecular Weight*Volume
= 0.1*214*2 = 42.8 g.
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Typical Concentration Problems
Molarity = moles x (1/volume in liters)
Volume = moles x (L/mole) = moles x (1/molarity)
Percent composition of any element in a compound is given by the following formula:
Molecular weight C17H35COONa
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Molarity problems
Molarity =Moles of solute/Volume of solution (1)
Here we have molarity = 0.207M
Volume of solution = 173.4 mL = 0.1734 (L)
Therefore moles of solute =0.207*.1734=0.036 (mole)
Because molecular weight of calcium acetate (CH3COO)2Ca =158.17 (g/mole