Calculate the molar concentration of a solution containing 4.75 of Ca(NO)3 in 0.200 L

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I was fine with finding the # of moles but now I'm having trouble dealing with grams. Could really use the help. Thanks

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molar concentration, solutes, and solvents

Solutions :
Calculate the molar concentration of a solution containing 4.75 of Ca(NO)3 in 0.200 L
Ca(NO)3 = 40.078 + (14.00674 + 15.9994) * 3 = 130.09642

When 130.09642 g of Ca(NO)3 dissolves in 1 liter solvent, solution is 1 M
Therefore, 1 g of Ca(NO)3 dissolve in 1 liter solvent , solution will be 1/130.09642 M
Or, for 4.75 of Ca(NO)3 in 0.200 L, the solution will be 4.5/130.09642 * 0.2
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Solution Summary

Molarity = No. of moles of solute / No. of liters of solution ; This formula can be used to calculate the molar concentrations, solutes and solvent. How many grams of solute are present are determined.

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Hey there. I am having trouble with this question.
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Could you please show the work. And no power points please.
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