See the attachment for the full problem statement.
Finding the mass of a reactant in an industrial equation:
Cu(NH3)4Cl2(aq) + 4 NH3(aq) + Cu(s) --> 2 Cu(NH3)4Cl(aq)
Please see the attached file.
0.2 mm = 0.02 cm.
The total volume of Cu to be removed = 10,100 * 7.15 * 11.5 * 0.02 * 0.85 = 14,118 ...
This solution finds the mass of a reactant in an etching reaction. The mass of a reactant is determined for industrial equations.