General Chemistry
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Boron has only two naturally occurring isotopes. The mass of boron-10 is 10.01294 amu and the mass of boron-11 is 11.00931 amu. Use the atomic mass of boron to calculate the relative abundance (%) of boron-10, and the relative abundance (%) of boron-11.
*I know the average amu for boron is 10.81. I don't understand how you solve this without having the relative abundance of one of the two isotopes.
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The expert examines the isotope occurrence and natural abundance. Neat, step-wise solution is provided.
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Let the relative abundance of B- 10 isotope be x% and that of the B- 11 isotope be y%
Then x + y = 100%
y = 100 - x --- (1)
Also, Average atomic mass ...
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