Explore BrainMass

Explore BrainMass

    Determination of Formula (MgO)

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Please see attached PDF to review the experiment. I'm looking for calculations to complete the table, and answers to the proceeding questions.

    © BrainMass Inc. brainmass.com December 24, 2021, 10:48 pm ad1c9bdddf
    https://brainmass.com/chemistry/stoichiometry/determination-formula-mgo-509895

    Attachments

    SOLUTION This solution is FREE courtesy of BrainMass!

    Calculations:
    Trial 1 Trial 2
    Wt of MgO 0.574 0.546
    Wt of O 0.222 0.213
    % MgO 61.32 60.99
    Mean % 61.16 61.16
    % error 1.69 1.14

    The weight of MgO is the weight of MgO+crucible - wt of crucible
    The weight of O is the wt of MgO - wt of Mg
    The % Mg is the (wt of Mg / wt of MgO ) x 100
    Mean % is the sum of both trials / 2
    Error % = (Experimental value - Theoretical value) x 100 / Theoretical value

    1. % Mg in MgO = (24.3 g / 40.3 g) x 100 = 60.30%

    % O in MgO = (15.99 g / 40.3 g) = 39.70%

    2. Amount of MgO = 2.033 g Mg x (1 mol Mg / 24.3 g Mg) x (2 mol MgO / 2 mol Mg) x (40.3 g MgO / 1 mol MgO) = 3.372 g MgO

    3. a) % Ca = (40. 078g / 56.0774) x 100 = 71.47%

    b) Amount of CaO = 1.358g Ca x (1 mol Ca / 40.078 g Ca) x (2 mol CaO / 2 mol Ca) x (56.1 g CaO / 1 mol CaO) = 1.900 g CaO

    4. When crucibles are heated, they must be cooled properly to room temperature. Even a slight change in temperature can result in lower weights as moisture will not be absorbed.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 10:48 pm ad1c9bdddf>
    https://brainmass.com/chemistry/stoichiometry/determination-formula-mgo-509895

    ADVERTISEMENT