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# de Broglie Wavelength of a Rifle Bullet

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A certain rifle bullet has a mass of 8.13 g. Calculate the de Broglie wavelength of the bullet traveling at 1721 miles per hour. Physical constants are found below:

Physical Constants
Quantity Symbol Value
speed of light in a vacuum c 2.99792458Ãƒ-108 m/s (exact)
Planck's constant h 6.6260755Ãƒ-10-34 JÂ·s
universal gas constant R 0.082057 LÂ·atm/(molÂ·K)
8.3145 J/(molÂ·K)
8.3145 m3Â·Pa/(molÂ·K)
8.3145 LÂ·kPa/(molÂ·K)
0.083145 LÂ·bar/(molÂ·K)
62.364 LÂ·Torr/(molÂ·K)
the Avogadro constant NA 6.02214179Ãƒ-1023 formula units/mol
mass of an electron me 9.109382Ãƒ-10-28 g
5.4858Ãƒ-10-4 amu
mass of a proton mp 1.67262171Ãƒ-10?24 g
1.007276466 amu
mass of a neutron mn 1.67492729Ãƒ-10?24 g
1.008664915 amu
charge on an electron e -1.602176487Ãƒ-10-19 C
Boltzmann constant k 1.3806503Ãƒ-10-23 J/K
Faraday constant F 96485 C/mol of electrons
Rydberg constant RH 1.096776Ãƒ-107 m-1
2.178688Ãƒ-10-18 J
3.288052Ãƒ-1015 s-1

de Broglie wavelength equation is lamda = h/mu

HINT:
Miles per hour is not the SI unit for velocity. Below are some useful relationships to obtain the velocity of the bullet in correct SI units.
(1.609 km)/(1 mile) (1 mile)/(3600 s) (?10?^3 m)/(1 km)

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## SOLUTION This solution is FREE courtesy of BrainMass!

First convert speed to SI unit.
v = 1721 mph = 1721 miles / hours = 1721* 1.609km / 1 mile * 1 mile / 3600s * 1000m / 1km

The mass of the bullet is m = 8.13g = 8.13*10^-3 kg

The de Broglie wavelength is calculated
lambda = h / mv = 6.6260755*10^-34 J*s / (8.13*10^-3 kg)*(769.2 m/s) = 1.06*10^-34 m

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

Â© BrainMass Inc. brainmass.com December 24, 2021, 10:44 pm ad1c9bdddf>
https://brainmass.com/chemistry/stoichiometry/de-broglie-wavelength-rifle-bullet-504045