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    De Broglie wavelength associated with a particle having kinetic

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    Prove that the De Broglie wavelength associated with a particle having kinetic energy K which is not negligible compared to its rest energy m_0 c^2 is given by

    lemda = [h/(m_0 K)^(1/2)](1 + K/2m_0 c^2)^(-1/2)

    The complete solution is in the attached file.

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    https://brainmass.com/physics/nuclear-particles/de-broglie-wavelength-associated-particle-kinetic-626715

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    The solution is in the attached file.

    Quantum Theory (2)
    By:- Thokchom Sarojkumar Sinha

    Prove that the De Broglie wavelength associated with a particle having kinetic energy K which is not negligible
    compared to its rest energy is given by

    Solution:- The relation between the kinetic energy K of a particle and its total relativistic energy
    is ...

    Solution Summary

    It proves that De Broglie wavelength associated with a particle
    having kinetic energy K which is not negligible compared to its
    rest energy m_0 c^2 is equal to
    lemda = [h/(m_0 K)^(1/2)](1 + K/2m_0 c^2)^(-1/2) .
    The solution is given in detail.
    This is mainly for showing the relation between the De Broglie wavelength
    and kinetic energy of a particle.

    $2.49

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