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    The De Broglie wavelength in A.U. of an electron

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    Show that the De Broglie wavelength in A.U. of an electron where a narrow beam
    of electrons is accelerated by a potential difference of V volts is given by

    lemda = [12.28/V^(1/2)][eV/(2m_o c^2) +1]^(1/2)

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    Solution Summary

    The Solution proves that the De Broglie wavelength in A.U. of an electron, where a narrow beam of electrons is accelerated by a potential difference is equal to lemda = [12.28/V^(1/2)][eV/(2m_o c^2) +1]^(1/2). This is mainly for showing the relation between the rest mass of electron and its De Broglie wavelength.

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