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Working with heat of vaporization

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I have attached the graphs. I don't think the first one is useful, but i needed to plot the data and find the heat of vaporization. Hence, the reason for the second graph. I know that the slope is equal to the heat of vaporization/RT but I don't think I am getting the right answer.

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https://brainmass.com/chemistry/physical-chemistry/working-heat-vaporization-9520

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Convert the temperarure values to Kelvin by the addition of 273. take ln of the vapor pressure values and plot. ...

Solution Summary

The heat of vaporization are analyzed. The slope which is equal to heat of vaporization are given. The solution explains each step and provides all mathematical steps.

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Triple point

The sublimation pressures of solid chlorine are 352 Pa at -112 C and 35 Pa at -126.5 C. The vapor pressures of liquid Chlorine are 1590 Pa at -100 C and 7830 Pa at -80C. Calculate a)heat of vaporization b)heat of sublimation c)heat of fusio d)triple point

I have already figured out the first three. The heat of sublimation is 31.2 kj/mole and the heat of vaporization is 22.l kj/mole. And since the heat of sublimation is equal to the heat of fusion plus the heat of vaporization then I just did simple algebra to get 9.1 kj/mol as the heat of fusion. However, the triple point is giving me trouble. I have found a number but I don't think that it is right. Can you please find the triple point for me.

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