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Working with heat of vaporization

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I have attached the graphs. I don't think the first one is useful, but i needed to plot the data and find the heat of vaporization. Hence, the reason for the second graph. I know that the slope is equal to the heat of vaporization/RT but I don't think I am getting the right answer.

https://brainmass.com/chemistry/physical-chemistry/working-heat-vaporization-9520

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Convert the temperarure values to Kelvin by the addition of 273. take ln of the vapor pressure values and plot. you haven't converted temp to kelvin scale and you took log instead of ln.

Plot ln p versus 1/T. The slope of this line is equal to the negative of the heat of vaporization divided by the gas constant.

We are making use of the Clausius-Clapeyron equation.

ln P = - [dH/R](1/T) + C

this is of the form y = mx + c with m as slope.

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