# Conversion Factor to SI Units

25. A meal replacement product was formulated to contain 380 mg Na per serving. If NaCl was used to achieve the intended Na level, and if this NaCl contained 100 ppm iodine, calculate the micrograms (to the nearest microgram) of iodine per serving in the finished product. Show your work.

26. An evaporator is used to concentrate cane sugar solutions. A feed of 10,000 kg/d of a solution containing 38% (wt %) sugar is evaporated producing a 74% (wt %) solution. Calculate the weight of solution produced and the amount of water removed. Show your work.

28. Determine the conversion factor to SI units:

a. an energy value of 1.7 Btu to kJ.

b. a pressure value of 14.69 psig (pounds per square inch [gauge] to kPa. Note: psia (pounds per square inch [absolute]) = psig + 14.69 (1 atm);

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25. A meal replacement product was formulated to contain 380 mg Na per serving. If NaCl was used to achieve the intended Na level, and if this NaCl contained 100 ppm iodine, calculate the micrograms (to the nearest microgram) of iodine per serving in the finished product. Show your work.

ppm of iodine in 1g of NaCl=100

1 mole of NaCl contains 23 grams of Na i.e., 2300 mg of Na. For providing 380 mg of Na, we need 0.165 moles of NaCl is required. This quantity of NaCl contains, ppm of Iodine which is equivalent to 0.000016481= mg of iodine

The conversion is done using the link

http://www.unitconversion.org/concentration-solution/milligrams-per-liter-to-parts-per-million-ppm-conversion.html

26. An evaporator is used to concentrate cane sugar solutions. A feed of 10,000 kg/d of a solution containing 38% (wt %) sugar is evaporated producing a 74% (wt %) solution. Calculate the weight of solution produced and the amount of water removed. Show your work.

Solution:

We have

So,

After the evaporation, 74% of solution is left. This gives 7400 Kg/d of solution. The weight of solution produced is 7400Kg/d and this has 38% of sugar and hence 62% of water.

Amount of water removed = (6200-4588)=1612Kg/d

For more help on weight percentages you can refer to http://dl.clackamas.edu/ch105-04/weight.htm

28. Determine the conversion factor to SI units:

a. an energy value of 1.7 Btu to kJ.

We have 1 Btu (British thermal unit) = 1,055.06 J=1.055kJ

So, 1.7 Btu= 1.7 x 1.055kJ=1.7935kJ

b. a pressure value of 14.69 psig (pounds per square inch [gauge] to kPa.

Note: psia (pounds per square inch [absolute]) = psig + 14.69 (1 atm);

We have 101.325 kPa = 14.7 psia. This gives 1 psia=

So,

For more help on conversions, you can refer to http://www.engineeringtoolbox.com/unit-converter-d_185.html

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