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    Calculate the work done (in Joules) when 33.3g of tin dissol

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    Calculate the work done (in Joules) when 33.3g of tin dissolves in excess acid at 1.04 atm and 22 degrees C. Assume ideal gas behavior.

    Sn(s) + 2H(aq) yields Sn2+(aq) + h2(g)

    I realize the equations PV=nRT and w=-p (change V) but have converted and can't seem to get it right?

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