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    pH and [OH-] of Basic Solution

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    [OH-] and the pH for each of the following strong base solutions:

    -- 0.082 M KOH

    -- 1.065 g of KOH in 500.0 mL of solution

    -- 10.0 mL of 0.0105 M Ca(OH)2 diluted to 500.0 mL

    -- a solution formed by mixing 10.0 mL of 0.015 M Ba(OH)2 with 40.0 mL of 7.5x10-3 M NaOH.

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    https://brainmass.com/chemistry/physical-chemistry/acid-base-equilibria-concentrations-ph-214935

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    Acid-Base Equilibria
    I am unsure of how to calculate

    [OH-] and the pH for each of the following strong base solutions:
    The pOH is calculated as pOH = - log[OH-]
    And pOH + pH = 14

    -- 0.082 M KOH
    In solution, KOH is a strong base and electrolyte, so
    KOH (aq) → K+ (aq) + OH- (aq)
    0.82 0.082
    Thus, the concentration of ...

    Solution Summary

    The solution provides examples of calculating the [OH-] and pH of several basic solutions.

    $2.19

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