One of the hydrogen emission lines has a wavelength of 486.0 nm.
Identify the values for n-initial and n-final for the transition giving rise to this line. (Enter as two integers, separated by a comma: e.g. 2,1 or 3,2 etc.)
Please could you explain how you got the nfinal and the n integer?© BrainMass Inc. brainmass.com October 9, 2019, 3:37 pm ad1c9bdddf
1/lambda = R*((1/n1^2) - (1/n2^2))
where, R = Rydberg constant = 1.09678 *10^7 /m
lambda = 486.0 nm = 486 *10^(-9) m
The solution describes how to obtain the n-final and n-initial values from a hydrogen emission spectrum with step-by-step calculations.