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    Octahedral Complex: oxidation state, isomers and CFSE

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    1. Determine is the oxidation state of the metal in each of the following complexes. Draw ALL linkage isomers and stereoisomers for each complex CLEARLY showing enantiomers. Where possible, label each isomer as cis, trans, fac, mer,  and/or . You must properly use shorthand notation for multidentate ligands. Note: do not consider the chirality of ligands and not all isomers can be labeled.

    a) K2[Cr(ox)2(NH3)(H2O)]
    b) [Rh(en)3]Cl3
    c) [WCl4F(OH)]
    d) NH4[Ni(CN)3(NH3)BrCl]
    e) [Co(en)(ox)(CO)(H2O)]
    f) Na2[PtCl2(NO2)2] (square planar)
    g) [FeCl2(CO)2(NH3)2](NO3)2

    2. For each series of octahedral complexes, predict which will have the largest and which will have the smallest value for . Briefly explain your answers. (Do not compare actual experimental values).

    a) [Fe(H2O)6]3+ [Fe(ox)3]3- [Fe(CN)6]3- [Fe(NO2)6]3-
    b) [Cr(SCN)6]3- [Cr(NH3)6]2+ [Cr(NH3)6]3+ [Cr(SCN)6]4-
    c) [Ir(H2O)6]3+ [Rh(H2O)6]3+ [Co(H2O)6]2+ [Co(H2O)6]3+
    d) [MoCl6]3- [MoF6]3- [MoCl6]2- [MoF6]2-
    e) [V(en)3]4+ [Nb(en)3]4+ [V(CN)6]3- [Nb(CN)6]3-

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    https://brainmass.com/chemistry/inorganic-chemistry/octahedral-complex-oxidation-state-isomers-cfse-614357

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    As you have several examples in each question, I will only work out one from each question, the rest can be done similarly.

    1. Determine is the oxidation state of the metal in each of the following complexes. Draw ALL linkage isomers and stereoisomers for each complex CLEARLY showing enantiomers. Where possible, label each isomer as cis, trans, fac, mer,  and/or . You must properly use shorthand notation for multidentate ligands. Note: do not consider the chirality of ligands and not all isomers can be labeled.

    a) K2[Cr(ox)2(NH3)(H2O)]
    While calculating oxidation state in a transition metal complex, pay attention to the ligands first. Oxalate ligand (ox) has a charge of -2. Ammonia (NH3) is neutral. Water (H2O) is neutral. Now take a look at the overall charge of the complex. As potassium (K) has a ...

    Solution Summary

    This solution offers one worked out example only for each of the questions, so that the student can follow the logical approach and work out the rest of the examples similarly.

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