[ Pd (H2O) (CO) (CN) I ] SO3
1. DRAW the isomers of this compound, and label them as geometric or optical (enatiomers): i.e. Use the [ ]SO3 *the drawing would be inside the brackets.
sodium Diamminedioxalatochromate (III)
2. DRAW the isomers of this compound, and label them as geometric or optical (enatiomers):
1. Which of the following molecules has NO net molecular dipole?
2. Which of the following molecules can hydrogen bond to another of the same compound?
3. What term best describes the relationship betwe
Fill in the table on page 2 as described below for each structural isomer of dichloropentane.
1) Write a condensed structural formula.
2) Write the IUPAC name.
3. Give the number of chiral carbons. Go back to the structural formula and put an asterisk (*) next to each chiral carbon.
4) Construct and us
This is more of a theoretical question I think. Co(NH3)5ClBr has two compounds forthat one formula. My question is how would I be able to demonstrate that the two compounds are different and how would I be able to explain what kind of isomerism it illustrates?
1. The C-O-C bond angle (degees) in the compound CH3-O-CH3 is closest to
2. Which of the following molecules would be expected to be MOST water soluble?
3. The relationship between CH3CH2OH and HOCH2C
Exercise 11: Draw structural formulas for all of the structural isomers of C4H10. Hint: There are two. You may find it helpful to build models to solve this exercise.
Exercise 12: Draw structural formulas for all of the structural isomers of C5H12. Hint: There are three.
Exercise 13: Draw structural formulas for all o
For questions 5-7, determine the oxidation state of the metal in each of the following complexes. Draw ALL linkage isomers and stereoisomersfor each complex CLEARLY showing enantiomers. Where possible, label each isomer as cis, trans, fac, mer, Δ and/or Λ. You must properly use shorthand notation for multidentate ligands.
Please help with the following problem.
When glucose is placed in water two stereoisomers are formed, one with the new OH on the opposite side of the ring than the 6th carbon, the α (alpha) isomer; and the other with the new OH group on the same side of the ring as the 6th carbon, β (beta) - anomer. Thus, a new chiral car