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    Finding the Number of Tobacco Mosaic Viruses

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    A certain strain of tobacco mosaic virus has Mm = 4 *10^7 kg/k mol. How many molecules of the virus are present in 1 cm^3 of a solution that contain0.1mg of virus per cm^3

    © BrainMass Inc. brainmass.com December 24, 2021, 4:48 pm ad1c9bdddf
    https://brainmass.com/chemistry/general-chemistry/finding-number-tobacco-mosaic-viruses-9005

    SOLUTION This solution is FREE courtesy of BrainMass!

    The mass of a molecule = m_0 = Mm/NA

    where NA = 6.02 *10^23 /mol = 6.02 * 10^26 k/mol

    m_0 = 4 *10^7/6.02 * 10^26

    The mass of virus molecules Mg in 1 cm^3 of the solution = 0.1 mg

    = 0.1 * 10^-6 kg

    Number of molecules in cm^3

    = 0.1 * 10^-6/m_0

    = 0.1 * 10^-6/{4 *10^7/6.02 * 10^26}

    = 1.5 * 10^12

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 4:48 pm ad1c9bdddf>
    https://brainmass.com/chemistry/general-chemistry/finding-number-tobacco-mosaic-viruses-9005

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