A certain strain of tobacco mosaic virus has Mm = 4 *10^7 kg/k mol. How many molecules of the virus are present in 1 cm^3 of a solution that contain0.1mg of virus per cm^3
The mass of a molecule = m_0 = Mm/NA
where NA = 6.02 *10^23 /mol = 6.02 * ...
The number of molecules of a virus is found. The solution explains each step and provides all mathematical steps.