If 23.96 kg of iron(III) oxide are combined with 11200 dm3 of carbon monoxide at STP, which substance would be the excess reactant--iron oxide, carbon monoxide, iron, carbon dioxide
dm stands for decimeter. There are 10 dm in 1 meter. dm3 is a unit of volume. Since you are working with a gas at STP, you can covert that volume into a # of moles. (Because 1 mol of ideal gas at STP has a volume of 22.4 L. You just need to convert dm3 into liters. It actually works out that all of the conversion factors cancel out, so that 1 dm3 = 1 L
1 liter = 1000 ml
1 milliliter = 1 cm3
10 dm = 100 cm or 1 dm = 10 cm so, 1 dm3 = (10 cm)^3 = 1000 cm3
(11200 dm3) * (1 dm3/ 1000 cm3) * (1 cm3 / 1 ml) * (1000 ml / L) = 11200 L
Now, you know that there are 22.4 L for every ...
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