Consider the following reaction.
CH4(g) + 2 O2(g) CO2(g) + 2 H2O(l) H = -891 kJ
Calculate the enthalpy change for each of the following cases.
(a) 3.00 g methane is burned in excess oxygen.
(b) 3.00 103 L methane gas at 738 torr and 21°C is burned in excess
An easy to understand solution is provided with all mathematical steps.