Refrigerators: Liquid Ammonia and Heat Energy
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Liquid ammonia, NH3(l), was once used in home refrigerators as the heat transfer fluid. The specific heat of the liquid is 4.7 J/g.K and that of the vapor is 2.2 J/g.K. The enthalpy of vaporization is 23.33 kJ/mol at the boiling point. If you heat 12 kg of liquid ammonia from
-50.0 °C to its boiling point of -33.3 °C, allow it to evaporate, and then continue warming to 0.0 °C, how much heat energy must you supply?
Please provide detailed explanation.
Thanks!
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Solution Summary
Are you confused about how to calculate the heat required to raise temperature and then evaporate a liquid? In this solution, a full description of this process is given with calculations and all work is shown.
Solution Preview
We have three stages of heat application, they include the following:
1) Heating the liquid (specific heat of 4.7 J/gK)
2) Evaporation (23330 J/mol)
3) Heating of the ...
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