Heat Absorption and Temperature Rise

Heat gained by a substance = mass x specific heat capacity x rise in temperature

or, dQ = m C dT

Here we need the specific heat capacity of water to solve this problem. From standard tables the specific heat of water is
4200 J/Kg K

Converting the temperature rise in the problem to Kelvin scale,
Temperature rise = 15 + 273 = 283 K

The mass of water is thus, m = dQ/(C dT)

= 2646/(4200 x 283)
= 0.0022 Kg

Answer is 2.2 mg

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