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Enthalpy / entropy / free energy

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Calculate the standard reaction enthalpy, entropy and free energy at 298K for the following reactions:
a) CH3OH(l) + O2 (g) → CO2 (g) + H2O(l)
b) P(s,white) + O2 (g) → P4O10 (s)
c) sucrose + H2O (l) → α glucose + β fructose

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Solution Summary

Enthalpy, entropy and free energy is examined. Three chemical equations are examined.

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Solution:
The standard enthalpy of reaction (H0reaction) can be solved from the standard enthalpy of formation (H0f) of reactants and products following the equation:
H0reaction = nH0f of products - nH0f of reactants
Where n and m are coefficients of products and reactants respectively in the balanced equation
The standard enthalpy of formation (H0f) values are found in literatures.
Note:
H0f of an element in its standard state is zero.

Similarly, the standard entropy of reaction (S0reaction) can be solved from the standard molar entropy (S0) of reactants and products following the equation:
S0reaction = nS0 of products - nS0 of reactants

Hence,
1. 2CH3OH(l) + 3O2 (g) ...

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