The equation for the reaction between iodide and bromate in acidic solution is
6I-(aq) + BrO3-(aq) + 6H+(aq) ---> 3I2(aq) + Br-(aq) + 3H2O
The rate of the reaction is followed by measuring the appearance of I2. The following data are obtained.
[I-] [BrO3-] [H+] Initial Rate (mol/L x s)
0.0020 0.0080 0.020 8.89 x 10-5
0.0040 0.0080 0.020 1.78 x 10-4
0.0020 0.0160 0.020 1.78 x 10-4
0.0020 0.0080 0.040 3.56 x 10-4
0.0015 0.0040 0.030 7.51 x 10-5
They want to know:
What is the order of the reaction with respect to each reactant?
Write the rate expression for the reaction
What is the hydrogen ion concentration when the rate is 5.00 x 10-4 mol/Lxs and [I-] = 1/2[BrO3-]= 0.0075M?
This is a kinetics experimental technique, and the only way you can find a Rate law....
Start with a generic rate law that has all the things you are testing in it....
Rate = k[I-]^x[BrO3-]^y[H+]^z
from the experiments you will be able to find the superscripts x, y, and z.
Here is how you do it.....
To find the effect that [I-] has on ...
The reaction rate between iodide and bromate in acidic solution is investigated.