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    Kinetics: Rate Law

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    i am clarifying this is not an assignemt is just practice questions. It was part of an old test that the teacher gave to us to practice .

    This are practice questions
    1. Calculate deltaH for the reaction P4O10 + 6 PCl3 ----? 10 Cl3PO

    From
    P4 + 6 Cl2 -----> 4 PCl3 deltaH = -1225.6 kJ
    P4 + 5 O2 -----> P4O10 deltaH = -2967.3 kJ
    PCl3 + Cl2 -----> PCl5 deltaH = -84.2 kJ
    PCl3 + ½ O2 ---> Cl3PO deltaH = -285.7 kJ

    2. Experiment

    ................[HgCl2]M............ [C2O4-2]M........ Rate(M/sec)
    1..................0.105....................0.15...............1.8 x 10-5
    2 .................0.105....................0.30...............7.2 x 10-5
    3...................0.052...................0.30...............3.5 x 10-5
    4..................0.052....................0.15...............8.9 x 10-6
    5 .................0.200....................0.45.....................X
    6..................0.35..........................y.................5.0 x 10-5

    a) Determine the rate law
    b) Calculate k
    c) Determine the values for X and Y
    3. Butadiene, C4H6, dimerizes to C8H12 with a 1st order rate constant of 0.014 L/mol sec. Starting with 0.025 M
    a) What will be the concentration after 3.00 minutes?
    b) How long will it take the concentration to drop to 0.0065 M?

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    https://brainmass.com/chemistry/chemical-kinetics/kinetics-rate-law-527558

    Solution Preview

    1.
    6PCl5 -> 6PCl3+6Cl2 (-6*(III))
    10PCl3+5O2 -> 10Cl3PO (10*(IV))
    P4O10 -> P4+5O2 (-(II)).
    (I)-6*(III)+10*(IV)-(II): we could obtain our reaction.
    Delta H = -1225.6-6*(-84.2)+10*(-285.7)-(-2967.3)= -610.1 kJ

    2.
    a)
    When [C2O4-2] ...

    Solution Summary

    The expert calculates deltaH for a reaction using kinetic rate laws.

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