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Kinetics: Rate Law

i am clarifying this is not an assignemt is just practice questions. It was part of an old test that the teacher gave to us to practice .

This are practice questions
1. Calculate deltaH for the reaction P4O10 + 6 PCl3 ----? 10 Cl3PO

From
P4 + 6 Cl2 -----> 4 PCl3 deltaH = -1225.6 kJ
P4 + 5 O2 -----> P4O10 deltaH = -2967.3 kJ
PCl3 + Cl2 -----> PCl5 deltaH = -84.2 kJ
PCl3 + ½ O2 ---> Cl3PO deltaH = -285.7 kJ

2. Experiment

................[HgCl2]M............ [C2O4-2]M........ Rate(M/sec)
1..................0.105....................0.15...............1.8 x 10-5
2 .................0.105....................0.30...............7.2 x 10-5
3...................0.052...................0.30...............3.5 x 10-5
4..................0.052....................0.15...............8.9 x 10-6
5 .................0.200....................0.45.....................X
6..................0.35..........................y.................5.0 x 10-5

a) Determine the rate law
b) Calculate k
c) Determine the values for X and Y
3. Butadiene, C4H6, dimerizes to C8H12 with a 1st order rate constant of 0.014 L/mol sec. Starting with 0.025 M
a) What will be the concentration after 3.00 minutes?
b) How long will it take the concentration to drop to 0.0065 M?

Solution Preview

1.
6PCl5 -> 6PCl3+6Cl2 (-6*(III))
10PCl3+5O2 -> 10Cl3PO (10*(IV))
P4O10 -> P4+5O2 (-(II)).
(I)-6*(III)+10*(IV)-(II): we could obtain our reaction.
Delta H = -1225.6-6*(-84.2)+10*(-285.7)-(-2967.3)= -610.1 kJ

2.
a)
When [C2O4-2] ...

Solution Summary

The expert calculates deltaH for a reaction using kinetic rate laws.

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