Equilibrium: Value of the constant
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The value of the equilibrium constant for the following reaction is 345.
A+2B(equilibrium sign)3C+D
What is the value of the equilibrium constant for the following reaction?
2A+4B(equilibrium sign)6C+2D
K=?
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Please see the attached file.
Write an equilibrium constant expression for the first chemical reaction:
where K = 345.
Similarly, for the second ...
Solution Summary
This Solution addresses the values of equilibrium constants for two questions.
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