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    Equilibrium: Value of the constant

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    The value of the equilibrium constant for the following reaction is 345.
    A+2B(equilibrium sign)3C+D

    What is the value of the equilibrium constant for the following reaction?

    2A+4B(equilibrium sign)6C+2D

    K=?

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    Solution Preview

    Please see the attached file.

    Write an equilibrium constant expression for the first chemical reaction:

    where K = 345.

    Similarly, for the second ...

    Solution Summary

    This Solution addresses the values of equilibrium constants for two questions.

    $2.49

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