Equilibrium: Value of the constant

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The value of the equilibrium constant for the following reaction is 345.
A+2B(equilibrium sign)3C+D

What is the value of the equilibrium constant for the following reaction?

2A+4B(equilibrium sign)6C+2D

K=?

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Solution Preview

Please see the attached file.

Write an equilibrium constant expression for the first chemical reaction:

where K = 345.

Similarly, for the second ...

Solution Summary

This Solution addresses the values of equilibrium constants for two questions.

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