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Electron Configuration and Lewis Structures

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How many electrons should appear in the Lewis structure of the following:
H3O+
SCN-
HCO3-
O2-
N2O4
BF3

Determine the formula change on the following
Cl-O
ClO4-

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Lewis electron count:

H3O + : The number of electrons on O are 6.
The number of electrons on H atom are 1.
Number of H atoms bonded to O by covalent bonds are 2.
Number of H atoms bonded to O by co-ordinate covalent bond are 1, this H atom
does donate an electron and hence the total electron count = 8.
SCN- : The number of electrons on C = 4
The number of electrons on S = 6
The number of electrons on N = 5
The negative charge indicates an additional electron
Thus the total electron count = 16.
HCO3- : The number of electrons on C = 4
The number of electrons on H = 1
...

Solution Summary

This solution determines the number of electrons on each element of a molecule as well as their formal charge to show how many electrons should appear in the Lewis Structure. The refractive index and mole fraction is used to determine formula change.

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