# Solubility at Equilibrium of AgOH.

10.0 mg of AgOH(s) is added to 350.0 mL of water with an initial pH of 11.00. The solubility equilibrium constant for the dissolution of AgOH (s) is Ksp = 1.5 x 10^-8. Determine the concentration of [Ag +] and the final pH at equilibrium.

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#### Solution Preview

AgOH(s) = Ag+ + OH- ----- (1)

Let's assume that x mg of AgOH(s) was dissolved at equilibrium. According to the equation (1), 1 mol of AgOH(s) produces 1 mol of Ag+ and 1 mol of OH-. Therefore ...

#### Solution Summary

This solution provides calculation and explanation in an attached Word document. Six steps of calculations and 113 words are used.

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