An Electrochemical Cell and Evaluating Solubility Product Constant
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Describe an electrochemical cell that would determine the solubility product constant at equilibrium for Chronium (III) hydroxide, then calculate the solubility product constant.
Balance these reduction potential half equations first:
Ox. Cr+3(aq) + 3e => Cr(s) -0.74v
Red. Cr(OH)3(s) + 3e => Cr(s) + 3OH-1(aq) -1.30v
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Solution Summary
This solution includes formula, calculations and explanation which the student can use to easily find K.
Solution Preview
Ok first of all the reaction you write with Ox next to it is actually a reduction as written but that is fixed easily as :
Ox. Cr+3(aq) + 3e < = Cr(s) ...
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