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Intracellular Molecule Synthesis.

Two intracellular molecules X and Y are both normally synthesized at a constant rate of 1000 molecules per second per cell. Molecules X is broken down slowly: each molecule of X survives on average for 100 seconds, Molecule Y is broken down 10 times faster, each molecule of Y survices on average for 10 seconds.

a. calculate how many molecules X and Y the cell contains at any time
b. If the rates of synthesis of both X and Y are suddenly increased tenfold to 10,000 molecules per second per cell without any change in their degradation rates-how many molecules of X and Y will there be after one second?
c. Which molecule would be preferred for rapid signaling? Why?
d. Which molecule would be preferred for slow signaling? Why?

Solution Preview

CELL SIGNALING MOLECULES

Two intracellular molecules X and Y are both normally synthesized at a constant rate of 1000 molecules per second per cell. Molecules X is broken down slowly: each molecule of X survives on average for 100 seconds, Molecule Y is broken down 10 times faster, each molecule of Y survives on average for 10 seconds.

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(a) Calculate how many molecules X and Y the cell contains at any time

Response:

Clearly, there will be lots more A than B.

Let's just simplify the question. If we look at molecule A, 1000 are made in one second. 1000 are made in the next second. 1000 more are made in the third second. Have any of these 3000 molecules disappeared yet? No, because they stay around for ...

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