# Simple Probability

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A factory finds,on average, 20% of the widgets produced by a given machine will be defective for certain specified requirements. If 10 widgets are selected at random from the day's production of this machine, find the probability:

a.) That exactly 2 will be defective

b.) That 2 or more will be defective

c.) That more than 5 will be defective

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Probability of defective item = p = 0.2

Probability of non defective = q = 1 - 0.2 = 0.8

a.)

Probability of exactly two defective widgets,

P= (10C2)*p^2*q^8

=>P = (10*9/2)*(0.2)^2 * (0.8)^8

=> P= 0.301989888

=> P== 0.302 --Answer

b.)

Probability of 2 ...

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- BEng, Allahabad University, India
- MSc , Pune University, India
- PhD (IP), Pune University, India

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