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Probability of Prophecy Fulfilled

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Based on the below account of prophecy and fulfillment how do I write out the answer based on the formula to solve the equation. I guess for statistics sake we could say that he could have ridden in on a camel, horse, or donkey. How do I go about doing this? Thanks for your help?

SO would the probability be .50 a yes he would or no he wouldn't?

AND if he has three animals to choose from (horse, camel, or donkey) would it be .33?

Does this help?

What you want to do is find the probability of each event. Then multiply the probabilities. This is written mathematically as P(A and B) = P(A) x P(B). IS THIS THE FORMULA TO USE AND IF SO HOW DO I WRITE IT OUT?

I've chosen the prophecy that the Messiah is to enter Jerusalem on a donkey (Prophesied in Zechariah 9:9; fulfilled in Matthew 21:6-11).

Zechariah 9:9 states, "Rejoice greatly, O Daughter of Zion! Shout, Daughter of Jerusalem! See, your king comes to you, righteous and having salvation, gentle and riding on a donkey, on a colt, the foal of a donkey" (NIV).

Matthew 21:6-11 states, "The disciples went and did as Jesus had instructed them. They brought the donkey and the colt, placed their cloaks on them, and Jesus sat on them. A very large crowd spread their cloaks on the road, while others cut branches from the trees and spread them on the road. The crowds that went ahead of him and those that followed shouted, "Hosanna to the Son of David!" "Blessed is he who comes in the name of the Lord!" "Hosanna in the highest!" When Jesus entered Jerusalem, the whole city was stirred and asked, "Who is this?" The crowds answered, "This is Jesus, the prophet from Nazareth in Galilee.""

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Solution Summary

Word doc attached calculates the probability of a Biblical prophecy being fulfilled.

Solution Preview

Please see the attached file.

Let A = Event that Jesus rode an animal when entering Jerusalem
P(A) = 0.5, ...

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