I have completed these but have no solutions with workings out

Use the binomial distribution to calculte the pobability of........Calculate the probability that the lifetime of a paticular device is........Investigate the degree of correlation between the results....Use a regression technique to estimate the job performance.......3 point averages.....etc

Solution: Here, p = 3% = 0.03, n = 10, q = 1 - 0.03 = 0.97
(i) For x = 0, P(x = 0) =
(ii) For x = 1, P(x = 1) =
(iii) For x = 2, P(x = 2) =
P(x<=1) = P(x = 0) + P(x = 1) = 0.9655
For a sample of 20, n = 20.
P(x = 0| n = 20) =
Probability that a day's output is accepted
= P(x = 0) + P(x = 1) + P(x = 2)*P(x = 0| n = 20) = 0.9655 + 0.0317*0.5438 = 0.9827

Probability that only one inspection is made = P(x<=1) = 0.9655
Probability that a second sample of 20 items is inspected P(x = 2) = 0.0317 (Since if exactly two items on the first sample are found defective, a second ...

Solution Summary

The expert examines mathematical computing solutions. The correlation between the results and job performances are given.

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