# Hypothesis Testing

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Background:The Waterhole bar & grill decided to run a special offer of a free fried zucchini appetizer with the purchase of a pitcher of beer & a sandwich for Monday nights only during the height of the baseball season. A loyal customer who loves baseball and grows vegetables agreed to supply the squash free. Management's objective was to exceed last year's average Monday night sales volume of $1,900. The data for the 12-week period during the fried zucchini special is as follows:

2200.0000

2400.0000

2100.0000

2250.0000

1800.0000

1950.0000

2500.0000

2600.0000

2650.0000

1600.0000

2700.0000

1850.0000

Column1

Mean 2216.666667

Standard Error 105.049291

Median 2225

Mode #N/A

Standard Deviation 363.9014186

Sample Variance 132424.2424

Kurtosis -1.184201101

Skewness -0.219902642

Range 1100

Minimum 1600

Maximum 2700

Sum 26600

Count 12

I am trying to solve what is the appropriate null hypotheses for the restaurant above to test: conclude that HO:mu<$1,900

and the value of the test statistic is: 3.01

I having difficulty understanding based on the data and at alpha=0.01, what can the restaurant above management conclude? Decide on: if sales during the zucchini special were no differ. from last year or Sales during the zucchini special decreased from last year or Sales during the zucchini special increased from last year or No conclusion can be drawn.

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##### Solution Summary

The solution answers the question(s) below.

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Ho: mu < $1900.

Solution:

<X> = sample mean = 2216.67

s = standard deviation = 363.9014186

n = 12 (small sample : t analysis)

degree of freedom = 12-1 = 11

because,

mu = <X> - t(a)*s/sqrt(n) < ...

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- BEng, Allahabad University, India
- MSc , Pune University, India
- PhD (IP), Pune University, India

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