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Chi-Squared and Regression

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A pharmaceutical company develops a new drug that helps obese patients who are not currently diabetic avoid contraction of diabetes. The conduct conducts a trial splitting a sample of 135 patients into two groups, a drug group and a placebo group. They then monitored the patients for 5 years and noted how many patients in each group contracted diabetes. The company wants to conduct a Chi-Squared test for Independence to assess whether their new drug has any effect on the contraction of diabetes amongst obese patients. Use this data to answer questions 1-3.

Number of Patients Drug Placebo
Contracted diabetes 51 18
Did not contract diabetes 39 27

1. Identify the correct critical value, χ_(α,df)^2.

2. Calculate the test statistic, χ_test^2.

3. The company statistician tells you that the p-value of the test is 0.0678. Compare the test statistic to the critical value. Compare the p-value to alpha. Is there statistically significant evidence to suggest that the drug is effective in preventing the contraction of diabetes? Explain why or why not.

An occupational therapist hypothesizes that there is a linear relationship between the number of years her patients spent in a desk job and the number of weeks it takes to complete therapy. The following table contains data from a sample of nine of her patients. Use this data to answer questions 4-6.

A B C D E F G H I J
Desk Job Yrs (j) 29.9 20 14.2 20.6 12.1 23.4 25.4 24.7 13.2 27.6
Therapy Wks (t) 12 8 6 7 5 11 9 11 5 12

4. Calculate and interpret the pearson's correlation coefficient between the variables J and T, r_jt, and the coefficient of determination between the variables J and T, r_jt^2. (20%)

5. Determine the coefficients of the least squares regression line for the following model between years in a desk job and weeks in therapy (equations on p.487): t_i=a+b*j_i+ε_i (20%)

6. Use the least-squares regression line to predict the expected number of weeks of therapy needed for a patient who has spent 22.5 years in a desk job. (20%)

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Solution Summary

Step-by-step explanations are shown for the questions for a pharmaceutical company. Computations and formulas are shown in the Excel file attached.

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Chi-Squared and Regression
A pharmaceutical company develops a new drug that helps obese patients who are not currently diabetic avoid contraction of diabetes. The conduct conducts a trial splitting a sample of 135 patients into two groups, a drug group and a placebo group. They then monitored the patients for 5 years and noted how many patients in each group contracted diabetes. The company wants to conduct a Chi-Squared test for Independence to assess whether their new drug has any effect on the contraction of diabetes amongst obese patients. Use this data to answer questions 1-3.

Number of Patients Drug Placebo
Contracted diabetes 51 18
Did not contract diabetes 39 27

The hypothesis statements are:
H0 : The row and column variables are independent.
H1 : The row and column variables are dependent.

1. Identify the correct critical value, χ_(α,df)^2.

Find Degrees of Freedom
Df = (r - 1)(c - 1) = (2 - 1)(2 -1) = 1

Find Critical Value of Chi-Square
Assume α = 0.05. Using Df = 1, and chi-square table,
Critical Value of Chi-Square = 3.841

2. ...

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  • MSc, California State Polytechnic University, Pomona
  • MBA, University of California, Riverside
  • BSc, California State Polytechnic University, Pomona
  • BSc, California State Polytechnic University, Pomona
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  • "Hello, thank you for your answer for my probability question. However, I think you interpreted the second and third question differently than was meant, as the assumption still stands that a person still independently ranks the n options first. The probability I am after is the probability that this independently determined ranking then is equal to one of the p fixed rankings. Similarly for the third question, where the x people choose their ranking independently, and then I want the probability that for x people this is equal to one particular ranking. I was wondering if you could help me with this. "
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