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# Perform a paired t-test in SPSS

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Research Scenario: A developmental psychologist is studying whether attachment can be improved upon by providing a parent training course. He has 10 parents who are seeking services to improve their children's attachment to them. He uses a measure of which higher scores indicate more secure attachments to caregivers and gave it to them before and after the 4 week parent training course. The attachment scores data are presented below for Before and After the parent training course. Assume the data are normally distributed. Did the parent training course improve attachment?

Before After
13 15
15 16
17 17
11 15
12 11
16 16
13 17
10 11
12 14
15 15

Answer the following questions based on the provided scenario.

14) Conduct a correlated groups t-test. Paste the appropriate SPSS output below.

15) Use the output to calculate r2 (show your work in the space provided). Interpret it (small, medium, large) based on the conventions for this effect size calculation.

16) Paste an appropriate SPSS graph (make sure you use the procedures outlined in this week's SPSS presentation - and don't forget to label your y axis "Attachment".

17) Write an APA-style Results section based on your analyses. All homework "Results sections" should follow the examples provided in the presentations. Include the effect size if you have a statistically significant finding. Remember to include a decision about the null hypothesis, report the confidence intervals, and refer to your Figure above.

##### Solution Summary

The solution consists of details of conducting a paired sample t-test in SPSS.

Solution provided by:
###### Education
• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
• "Thank you"
• "Thank you very much for your valuable time and assistance!"

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