In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H.Firtle discuss a survey of marketing professionals, the results of which were originally published by Ishm
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In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H.Firtle discuss a survey of marketing professionals, the results of which were originally published by Ishmael P. Akoah and Edward A. Riordan in the Journal of Marketing Research. In the study, randomly selected marketing researchers were presented with various scenarios involving ethical issues such as confidentiality, conflict of interest, and social acceptability. The marketing researchers were asked to indicate whether they approved or disapproved of the actions described in each scenario. For instance, one scenario that involved the issue of confidentiality was described as follows:
Use of ultraviolet ink: A project director went to the marketing research director's office and requested permission to use an ultraviolet ink to precode a questionnaire for a mail survey. The project director pointed out that although the cover letter promised confidentiality, respondent identification was needed to permit adequate cross-tabulations of the data. The marketing research director gave approval.
Of the 205 marketing researchers who participated in the survey, 117 said they disapproved of the actions taken in the scenario.
Construct a 90%, 95%, and 99% confidence interval for the marketing researchers to disapprove the actions taken in the ultraviolet ink scenario.
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The essentials of marketing research for William R. Dillion and Thomas J. Madden is determined.
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Solution. p^=117/205=0.571, n=205.
1) For a 90% confidence level, z=1.645. So, a 90% confidence interval for the marketing researchers to disapprove the actions taken in the ultraviolet ink scenario is
(p^- z*sqrt[p^*(1-p^)/n], p^+ ...
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- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
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