One-Factor Experiment for equal number of Observations
A company wishes to test 4 different types of tires, A, B, C, D. The lifetimes of the tires, as determined from their treads, are given ( in thousands of miles ) in table below, where each type has been tried on 6 similar automobiles assigned at random to tires. Test at the
(a) 0.05 level (b) 0.01 level whether there is a difference in tires.
I II III IV V VI
A 33 38 36 40 31 35
B 32 40 42 38 30 34
C 31 37 35 33 34 30
D 29 34 32 30 33 31
SSA = 77.5032
SSW = 216.333
SST = SSA + SSW = 77.503 +216.333 = 293.836
Using the critical value table of F-distribution, we see that the critical value of F for 3, 20 degrees of freedom at 0.05 ...
Solution to the posted problem is given in the attached file in a very simple language and is explained with every minute detail so that the student could easily follow the procedure and use this solution as a model solution to solve other similar problems on his/her own.