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ANOVA from output table

ANOVA: Single Factor

SUMMARY
Groups Count Sum Average Variance
Column 1 70 29296 418.5143 2069.732
Column 2 66 26720 404.8485 1274.254
Column 3 73 29468 403.6712 938.696

ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 9546.877 2 4773.438 3.353505 0.036881 3.039723
Within Groups 293224.1 206 1423.418

Total 302771 208

The P value is < &#945;, reject the null hypothesis of equal means and concludes that at least one population means is different from the others.

P- value is 0.03, which is less than the significance level 0.05.

HERE IS MY SECOND PROBLEM

SUMMARY
Groups Count Sum Average Variance
Column 1 9 1194 132.6667 17.5
Column 2 9 1210 134.4444 11.27778
Column 3 9 1243 138.1111 22.61111

ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 138.7407 2 69.37037 4.04973 0.030518 3.402832
Within Groups 411.1111 24 17.12963

Total 549.8519 26

The P value is < alpha, reject the null hypothesis of equal means and conclude that at least one population means is different from the others.

Solution Preview

Please see attached file.

Conclusion: Since calculated F test is more than critical value we reject ...

Solution Summary

An ANOVA performed the outputted results given in the problem is done.

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