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    Pulley

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    Two blocks of mass m and 3m are slug over a pulley by a massless rope. The massess are initially at the same height. The pulley is a uniform solid disk of mass 12m and radius R. The total length of the rope including the part that is slung over the pullley is L The masses are released at time t = 0
    Determine the time it takes for the pulley to complete one revolution
    Determine the time that it takes for the smaller mass to crash into the pulley.

    © BrainMass Inc. brainmass.com February 24, 2021, 2:17 pm ad1c9bdddf
    https://brainmass.com/physics/torques/time-takes-pulley-complete-one-revolution-11436

    Solution Preview

    Torque acting on the pulley= (3m-m) x g x R= 2 m g R ----(1)
    Torque= I alpha

    Where I = moment of inertia = ½ M R ^2
    And alpha = angular acceleration
    M= mass of the pulley = 12 m
    Therefore I= ½ x (12 m ) R ^2= 6 m R^2

    Torque= I alpha = 6 m R^2 x alpha ----------(2)
    Equating 1 and ...

    Solution Summary

    The solution determines the time it takes for the pulley to complete one revolution and the time that it takes for the smaller mass to crash into the pulley.

    $2.19

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