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Calculating the holding torque in a gear box.

A gear box has the input power 10kw at 2400 rev/min. The gear ratio is a reduction of 2 to 1. The efficiency is 98%. What is the holding torque required?

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The Power to gear 1 is 10Kw. The power received by gear 2 is a little bit lower, it means, 0.98*10 Kw ( 9.8 Kw).

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Solution Summary

This full solution uses the equation Power = Torque (T) * rotational speed (w). 100 words.