1. Suppose a man pushes a small car on level ground. He pushes with a force of 400 N, and the 800kg car accelerates at a rate of 0.30 m/s2.

(a) What is the net force on the car?
(b) Draw a force diagram for the car, showing the force of pushing, the force of friction, and weight, and the upward (normal) force of the ground.
(c) Determine the force of friction.
(d) Suppose the man stops pushing. What then would be the acceleration of the car (magnitude and direction)?

2. Suppose a bowling ball weighs 12 pounds on the surface of the Earth. Now suppose we take the ball to a distance D from the center of the Earth, where D is 60 times the Earth's radius. What is the force of Earth's gravity on the bowling ball in this case? If you dropped the bowling ball from that height, what would be its acceleration, at first? (You don't need to know the constant G or the mass or radius of the Earth.)

Solution Preview

1. (a) The acceleration of the car would be equal to the net force along the direction of movement divided by the total mass.

Fnet = net force
m = total mass
a = Fnet / m
0.3 = Fnet / 800
Fnet = 240 N

(b) See file attached

(c) The force he applies: Fapp=400N Frictional force: Ffrict total mass: m = 800 kg acceleration: a= 0.3 m/s2

The net force on the car would be the sum of applied force and ...

Solution Summary

Calculating the net force and acceleration of a car and a bowling ball.

... direction of the displacement/motion of the car. Substituting this value of the acceleration and other ... for finding the magnitude of horizontal net force. ...

... is pushed forward simply because it is in the way of the car. ... is applied by chair on the man making net force on the man zero and hence acceleration zero. ...

... Which is the magnitude of the force that opposes said movement? acceleration=a= 0.175 m/s^2 mass of the car=m= 1270 Kg. Net force= ma= 222.25 N =1270*0.175. ...

...Acceleration of the crate = Net force/Mass = 113/32 = 3.53 m/s2. Force exerted on the car by static friction = Centripetal force = mv2/R = 1200x152/57 = 43. ...

... there is no accleration of car, the car is travelling ... second Law is used to detemine the net acceleration of a ... applied to that body and the net force acting on ...

... If the car moves away from the origin from ... is decreasing, the rate of change (the acceleration) is negative ... And since the total net force is proportional to the ...

... she exerts on the box, the total net force is no ... By the definition of acceleration (the rate of change in the ... 5. Two students push a small car down the driveway ...

... Any further increase in the deceleration of the car results in ... 5.3 As per Newton's second law of motion, acceleration of link 3 = Net force/Mass = (F23 ...

...Acceleration a = Net force/Mass ... 3920 - 2T1)/400 = 0.75/2 (acceleration of C is ½ of acceleration of D ... M = 500 x 106 g or 500 x 103 kg Mass of the car = m = 1500 ...