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# Mathematical equation for my kinetic entity ring

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I have come up with the hypothesis of the existence of a kinetic entity ring that could explain the physics behind Einstein's theory of relativity. I have posted my theory in my webpage at www.sc-innovation.com/entity.html. I am not a mathematician and so cannot come up with the equation for my kinetic entity ring. I hope someone could do this for me. Please go to my webpage above to have a clearer idea of my kinetic entity ring is about.
I want to come up with an equation from my kinetic entity ring about "Time Dilation". Suppose there are two clocks, one at rest and the other is in a space ship travelling at high speed. Initially both clocks show the same time. As time goes by the two clocks will show time differences. I want an equation to show the relationship between their time differences. I want you to comment on the "Time Dilation" from my kinetic entity ring to that of Einstein's theory of relativity.

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I think, the way you are trying to propose your theory is really a great sprit and adventure. You are doing really a great job.
<br>
<br>Here I've tried to derive the relation for time dilation and hope that will satisfy you.
<br>
<br>let the angle between c and v is Q(read as theta)
<br>therefore,
<br>cos(Q) = v/c (c is speed of light)
<br>therefore vertical component i.e., sine component:
<br>sin(Q) = sqrt( 1 - cos^2(Q)) = ( 1 - (v/c)^2)
<br>therefore,
<br>vertical component of displacement = s*sin(Q)
<br>hence,
<br>time lapse:
<br>t = s*sin(Q)/c = (s/c) * sin(Q) = t' * sin(Q)
<br>=> t = t' * sqrt(1 - (v/c)^2)
<br>where t is the proper time and t' is the rest frame measured time.
<br>therefore,
<br>time difference = t' - ...

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###### Education
• MSc , Pune University, India
• PhD (IP), Pune University, India
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