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    Determine energy and momentum of photon produced in a collision

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    An electron moving at a speed of 0.60c collides head on with a positron of speed at 0.60c. Determine the energy and momentum of each photon produced in the process.

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    Solution Preview

    In the case of an electron and positron, the energy balance can be represented as:

    2 m0 c^2 + KE(-e) + KE(+e) = 2 h*f ----------(1)

    The first term represents the rest energy of both particles, the second and third terms are the kinetic energies just before the collision, and the term on the right-hand side of the equation represents the creating of two photons, each having a the same frequency f and energy h*f . ...

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