An electron moving at a speed of 0.60c collides head on with a positron of speed at 0.60c. Determine the energy and momentum of each photon produced in the process.© BrainMass Inc. brainmass.com February 24, 2021, 2:23 pm ad1c9bdddf
In the case of an electron and positron, the energy balance can be represented as:
2 m0 c^2 + KE(-e) + KE(+e) = 2 h*f ----------(1)
The first term represents the rest energy of both particles, the second and third terms are the kinetic energies just before the collision, and the term on the right-hand side of the equation represents the creating of two photons, each having a the same frequency f and energy h*f . ...
With good explanations and computations, the problem is solved.