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Electromagnetic Waves and Photoelectric Effect

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Light of wavelength 345 nm shines on a piece of calcium metal. What is the speed of the ejected electron? (Light energy greater than that of the work function of calcium ends up as kinetic energy of the ejected electron.) Work function for calcium= 4.34 x 10^-19 J.

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Solution Summary

We have the Einstein relation for photoelectric effect as h v = h vo + (1/2) m v^2 = h vo + 0.5 m V^2.

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We have the Einstein relation for photoelectric effect as,

h v = h vo + (1/2) m v^2 = h vo + 0.5 m V^2 ----(1)

h = 6.625*10^-34 J S, the Planks constant, m = ...

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