Explore BrainMass
Share

Interferometry Fabry-Perot

This content was STOLEN from BrainMass.com - View the original, and get the already-completed solution here!

3) A Fabry-Perot interferometer with fixed plate spacing t = 1.50mm is used to examine filtered light from a helium lamp, with wavelength lambda = 587.56nm. The plates have reflectance R = 0.950.

a) What is the free spectral range (in nm) for this spacing t and wavelength lambda?

b) What is the smallest resolvable wavelength difference for this setup?

© BrainMass Inc. brainmass.com October 24, 2018, 7:50 pm ad1c9bdddf
https://brainmass.com/physics/optics/interferometry-fabry-perot-80540

Attachments

Solution Preview

Hello and thank you for posting your question to Brainmass!

The solution is attached below (next to the paperclip icon) in two formats. one is in Word XP ...

Solution Summary

This solution provides explanation of how to find the free spectral range, and what the smallest resolvable wavelength is.

$2.19
See Also This Related BrainMass Solution

Fabry-Perot interferometer

A Fabry-Perot interferometer is to be used to resolve the mode structure of a He-Ne laser operating at 632.8 nm. The frequency separation between the modes is 150 MHz. The plates are separated by an air gap and have a reflectance (r^2) of 0.999.
(a) What is the coefficient of finesse of the instrument?
(b) What is the resolving power required?
(c) What plate spacing is required?
(d) What is the free spectral range of the instrument under these conditions?
(e) What is the minimum resolvable wavelength interval under these conditions?

View Full Posting Details